Answer :

To find the increase in temperature when 84 KJ of heat is supplied to 2 kg of water, we can use the formula for heat transfer:

[tex]\[ \Delta T = \frac{Q}{m \times c} \][/tex]

where:
- [tex]\(\Delta T\)[/tex] is the change in temperature,
- [tex]\(Q\)[/tex] is the heat supplied,
- [tex]\(m\)[/tex] is the mass of the substance,
- [tex]\(c\)[/tex] is the specific heat capacity of the substance.

Let's break it down step-by-step:

1. Identify Given Values:
- Heat supplied ([tex]\(Q\)[/tex]) = 84 KJ
- Mass of water ([tex]\(m\)[/tex]) = 2 kg
- Specific heat capacity of water ([tex]\(c\)[/tex]) = 4.186 KJ/(kg°C)

2. Use the Formula:
- [tex]\(\Delta T = \frac{84 \text{ KJ}}{2 \text{ kg} \times 4.186 \text{ KJ/(kg°C)}}\)[/tex]

3. Calculate:
- First, multiply the mass of water and its specific heat capacity: [tex]\(2 \times 4.186 = 8.372 \text{ KJ/°C}\)[/tex].
- Next, divide the heat supplied by the result from the previous step: [tex]\(\frac{84}{8.372} \approx 10.03°C\)[/tex].

Therefore, the increase in temperature of the water is approximately [tex]\(10.03°C\)[/tex].

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Rewritten by : Barada