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Answer :
Final answer:
The amount of heat that could be transferred from a hot water bottle containing 705g of water that cools from 67.0 °C to 37.1 °C to sore muscles is approximately 87.7 kilojoules.
Explanation:
To calculate the amount of heat transferred from the hot water to the sore muscles, we can use the formula for heat transfer which is Q=mcΔT, where:
- Q is the heat transferred (which we want to find)
- m is the mass of the water (705g),
- c is the specific heat capacity for water (4.18 J/g°C), and
- ΔT is the change in temperature (67.0 °C - 37.1 °C = 29.9 °C).
Plugging in these values gives us: Q = 705g * 4.18 J/g°C * 29.9 °C = 87,722 J. Since kilojoules are requested, we convert Joules to kilojoules by dividing by 1000. Therefore, about 87.7 kJ of heat could be transferred from the hot water bottle to sore muscles.
Learn more about Heat Transfer here:
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