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The band's manager earns a monthly rate plus [tex]$20[/tex] for each show booked. Last month, the manager earned at least [tex]\$170[/tex].

Let [tex]x[/tex] = number of gigs booked
Let [tex]y[/tex] = monthly rate

Choose the inequality that relates the manager's number of gigs and monthly rate to last month's earnings.

A. [tex]x + 20y < 170[/tex]
B. [tex]x + y < 170[/tex]
C. [tex]y + 20x > 170[/tex]
D. [tex]20x + y \geq 170[/tex]

Answer :

To solve this problem, we need to find the correct inequality that describes the relationship between the number of gigs booked, the monthly rate, and the total earnings of the band's manager for the last month.

Given:
- The manager earns a fixed monthly rate, which we'll call [tex]\( y \)[/tex].
- The manager also earns [tex]$20 for each gig booked, represented by \( 20x \).
- Last month, the manager earned at least $[/tex]170 in total.

We are trying to express this situation as an inequality that represents the total earnings from both the fixed monthly rate and the gigs.

The manager's total earnings is the sum of the base monthly rate plus the earnings from the gigs:
[tex]\[ \text{Total earnings} = y + 20x \][/tex]

Since the manager earned at least [tex]$170, we need the total earnings to be greater than or equal to $[/tex]170:
[tex]\[ y + 20x \geq 170 \][/tex]

Now, let's see which option matches this logic:

1. [tex]\( x + 20y < 170 \)[/tex]
2. [tex]\( x + y < 170 \)[/tex]
3. [tex]\( y + 20x > 170 \)[/tex]
4. [tex]\( 20x + y \geq 170 \)[/tex]

The inequality that represents the manager earning at least $170 is:
[tex]\[ 20x + y \geq 170 \][/tex]

So, the correct choice is: [tex]\( 20x + y \geq 170 \)[/tex].

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