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A camera is lowered into the sea in various stages. What depth does the camera reach after the following movements? (Heights above sea level are positive numbers; heights below are negative numbers.)

a) The camera is lowered from a height of 1.3 metres. It is lowered in four stages of 0.6 metres and three stages of 0.7 metres.
- Depth reached: ______ m

b) The camera is lowered from a height of 2.2 metres. It is lowered in five stages of 0.8 metres and four stages of 0.9 metres.
- Depth reached: ______ m

c) The camera is lowered from a height of 2.5 metres. It is lowered in six stages of 0.4 metres, three stages of 0.7 metres, and five stages of 0.9 metres.
- Depth reached: ______ m

Answer :

Final answer:

To find the depth reached by the camera after different movements, we need to calculate the sum of the negative heights. Adding up these negative heights gives us the depth reached. For the given scenarios, the depths reached are -10.7 meters, -8.8 meters, and -10 meters respectively.


Explanation:

To find the depth that the camera reaches, we need to calculate the sum of the negative heights. For example, in part a, the camera is lowered from a height of 1-3 meters and then lowered in four stages of 0-6 meters and three stages of 0.7 meters. To find the depth reached, we add the negative heights: -1-(-3)+(-0.6)+(-1.8)+(-0.6)+(-0.6)+(-0.7)+(-0.7)+(--0.7) = -10.7 meters.

In part b, the camera is lowered from a height of 2.2 meters and then lowered in five stages of 0.8 meters and four stages of 0.9 meters. Adding the negative heights: -2.2+(-0.8)+(-0.8)+(-0.8)+(-0.8)+(-0.8)+(-0.9)+(-0.9)+(-0.9)+(-0.9) = -8.8 meters.

For part c, the camera is lowered from a height of 2.5 meters and then lowered in six stages of 0.4 meters, three stages of 0.7 meters, and five stages of 0.9 meters. Adding the negative heights: -2.5+(-0.4)+(-0.4)+(-0.4)+(-0.4)+(-0.4)+(-0.4)+(-0.7)+(-0.7)+(-0.7)+(-0.9)+(-0.9)+(-0.9)+(-0.9)+(-0.9) = -10 meters.


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