We appreciate your visit to 1 Wine is approximately 12 ethanol tex C 2H 5OH tex by volume Ethanol has a molar mass of 46 06 g mol and a. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
1.541 moles of ethanol are present in a 750 mL bottle of wine.
How to find the number of moles ?
Number of moles = [tex]\frac{\text{Mass}}{\text{Molar mass}}[/tex]
What is Density ?
The substance per unit volume is called Density. SI unit of density is kg/m.
It is expressed as:
Density = [tex]\frac{\text{Mass}}{\text{Volume}}[/tex]
Volume of ethanol = 12%
= [tex]\frac{12}{100}[/tex]
= 0.12
Volume of ethanol = 0.12 × 750
= 90
Density of ethanol = [tex]\frac{\text{Mass of ethanol}}{\text{Volume of ethanol}}[/tex]
0.789 g/mL = [tex]\frac{\text{Mass of ethanol}}{90}[/tex]
Mass of ethanol = 0.789 × 90
= 71.01 g
Now put the value in above formula we get
Number of moles = [tex]\frac{\text{Mass}}{\text{Molar mass}}[/tex]
= [tex]\frac{71.01\ g}{46.06\ \text{g/mol}}[/tex]
= 1.541 mol
Thus from the above conclusion we can say that 1.541 moles of ethanol are present in a 750 mL bottle of wine.
Learn more about the Number of mole here: https://brainly.com/question/1575466
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Rewritten by : Barada
Hey there!:
Total volume of wine = 750ml
volume ℅ of ethanol = 12
%
volume of ethanol = (12ml/100ml)*750ml = 90ml
Density of Ethanol = 0.789 g/ml
Mass of Ethanol = 0.789 g/ml × 90ml = 71.01 g
Molar mass of ethanol = 46 g/mol Nº of mole of ethanol = Mass/molar mass
=> 71.01 g /46(g/mol)= 1.5437 moles
Hope this helps!
