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Which polynomial lists the powers in descending order?

A. [tex]x^8 + 10x^2 + 8x^3 + 3x^6 - 2[/tex]

B. [tex]3x^6 + 10x^2 + x^8 + 8x^3 - 2[/tex]

C. [tex]10x^2 + 8x^3 + x^8 - 2 + 3x^6[/tex]

D. [tex]x^8 + 3x^6 + 8x^3 + 10x^2 - 2[/tex]

Answer :

To determine which polynomial lists the powers in descending order, we need to organize the terms from the highest power of [tex]\( x \)[/tex] to the lowest power.

Let's look at each option individually:

Option A: [tex]\( x^8 + 10x^2 + 8x^3 + 3x^6 - 2 \)[/tex]

- Powers of [tex]\( x \)[/tex]: [tex]\( 8, 2, 3, 6, 0 \)[/tex]
- In order: [tex]\( x^8, 3x^6, 8x^3, 10x^2, -2 \)[/tex]

Option B: [tex]\( 3x^6 + 10x^2 + x^8 + 8x^3 - 2 \)[/tex]

- Powers of [tex]\( x \)[/tex]: [tex]\( 6, 2, 8, 3, 0 \)[/tex]
- In order: [tex]\( x^8, 3x^6, 8x^3, 10x^2, -2 \)[/tex]

Option C: [tex]\( 10x^2 + 8x^3 + x^8 - 2 + 3x^6 \)[/tex]

- Powers of [tex]\( x \)[/tex]: [tex]\( 2, 3, 8, 0, 6 \)[/tex]
- In order: [tex]\( x^8, 3x^6, 8x^3, 10x^2, -2 \)[/tex]

Option D: [tex]\( x^8 + 3x^6 + 8x^3 + 10x^2 - 2 \)[/tex]

- Powers of [tex]\( x \)[/tex]: [tex]\( 8, 6, 3, 2, 0 \)[/tex]
- Already in order: [tex]\( x^8, 3x^6, 8x^3, 10x^2, -2 \)[/tex]

Option D lists the terms in descending order of the powers: [tex]\( x^8, x^6, x^3, x^2, \)[/tex] and the constant term [tex]\(-2\)[/tex]. Therefore, the correct answer is D.

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