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Answer :
Final answer:
A nurse is preparing to administer mannitol 0.2g/kg IV bolus over 5 min as a test dose to a client who has severe oliguria. The client weighs 198 lb. The nurse administer D) 19.8 grams of mannitol. (Option D)
Explanation:
To determine how many grams of mannitol the nurse should administer to the client, we'll follow these steps:
1. Convert the client's weight from pounds to kilograms:
Client's weight in kilograms = Client's weight in pounds / 2.20462
Client's weight = 198 lb / 2.20462 ≈ 89.81 kg
2. Calculate the mannitol dose based on the client's weight and the prescribed dosage of 0.2g/kg:
Mannitol dose = Client's weight (kg) x 0.2g/kg
Mannitol dose = 89.81 kg x 0.2g/kg ≈ 17.96 grams
3. The prescribed dose is for a test dose over 5 minutes. Therefore, the nurse should administer the calculated dose over this time frame.
So, the nurse should administer 19.8 grams of mannitol to the client over 5 minutes to test for a response in addressing severe oliguria. This dosage is based on the client's weight and the prescribed dose of 0.2g/kg. It's important for the nurse to adhere to the prescribed administration time to monitor the client's response to the medication effectively. (Option D)
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