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Identify the oxidation state of Sr in [tex]Sr(s)[/tex].

\[Sr(s) + 2HF(aq) \rightarrow SrF_2(aq) + H_2(g)\]

A. +1
B. -3
C. -1
D. 0
E. -2

Answer :

To determine the oxidation state of strontium (Sr) in [tex]\( Sr(s) \)[/tex], we need to consider some basic chemistry rules regarding oxidation states.

1. Pure Element Rule: The oxidation state of any pure element in its standard state is always 0. This is because there is no gain or loss of electrons occurring in the elemental form.

2. Applying the Rule: In the chemical equation [tex]\( Sr(s) + 2 HF(aq) \rightarrow SrF_2(aq) + H_2(g) \)[/tex], Sr is present in its elemental form [tex]\( Sr(s) \)[/tex]. Therefore, according to the rule above, the oxidation state of Sr in this state is 0.

So, the oxidation state of Sr in [tex]\( Sr(s) \)[/tex] is 0.

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