Answer :

The density of titanium in this block is 4.51 g/cm³.

Here's how to calculate the density of titanium in g/cm³:

**1. Convert all dimensions to the same unit (cm):**

* Width (w) = 15.0 mm * (1 cm / 10 mm) = 1.50 cm

* Height (h) = 1.00 dm * (10 cm / 1 dm) = 10.0 cm

**2. Calculate the volume (V) of the block:**

V = length (l) * width (w) * height (h)

V = 25.0 cm * 1.50 cm * 10.0 cm = 375 cm³

**3. Convert the mass (m) to grams:**

m = 1.69 kg * (1000 g / 1 kg) = 1690 g

**4. Calculate the density (ρ):**

ρ = m / V

ρ = 1690 g / 375 cm³ = 4.51 g/cm³

Therefore, the density of titanium in this block is 4.51 g/cm³.

The probable question may be:

A block of titanium of dimensions of 25.0 cm × 15.0 mm×1.00 dm has a mass of 1.69 kg. How do you calculate the density of titanium in g/cm³?

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Rewritten by : Barada