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A police officer is investigating an auto accident. The officer looks at the evidence file and finds a tab from a local bar in his pocket. The bar tab was started at 9:15 PM and shows that the 185 lb deceased male had 5 beers. The accident occurred at 2:30 AM. At the time of the accident, what was the BAC of the person?

Answer :

Final answer:

The BAC of the person at the time of the accident would be approximately -15 mmol/L (-75 mg/dL), indicating that the person had already metabolized more alcohol than was present in their system.

Explanation:

The blood alcohol concentration (BAC) at the time of the accident can be calculated by considering the rate at which alcohol is metabolized by the body. On average, the body metabolizes alcohol at a rate of about 3.3 mmol/L (15 mg/dL) per hour.

The accident occurred at 2:30 AM, which means 5 hours passed since the bar tab was started at 9:15 PM. During this time, the body would have metabolized approximately 5 * 3.3 = 16.5 mmol/L (75 mg/dL) of alcohol.

To calculate the BAC, we need to take into account the initial concentration of alcohol in the body after consuming 5 beers.

Each beer typically contains around 14 grams of alcohol, so 5 beers would contain 5 * 14 = 70 grams of alcohol. Converting this to mmol/L, we get 70 / 46 = 1.52 mmol/L (approximately).

Therefore, the BAC of the person at the time of the accident would be the initial concentration of alcohol (1.52 mmol/L) minus the amount metabolized (16.5 mmol/L), which is approximately -15 mmol/L (-75 mg/dL).

It is important to note that a negative BAC value indicates that the person had already metabolized more alcohol than was present in their system at the time of the accident.

Learn more about Blood Alcohol Concentration here:

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