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Answer :
Answer
Cp = 0.00204 J/g °C
Explanation
Given:
Mass of copper = 98.5 g
Initial temperature of copper = 221.3C
Volume of water = 425.0 ml = 0.425 L
Final temperature = 22.5C
Required: Specific heat of copper
Solution
Q = m x Cp x Dt where Q is the heat, m is the mass, Cp is the specific heat capacity and Dt is the change in temperature.
Step 1: Calculate the mass of water
density = mass/volume
mass = density x volume
mass = 1 g/L x 0.425 L
mass = 0.425 g
Step 2: Calculate Cp
Q metal = -Qwater
m x Cp x Dt = -(m x Cp x Dt)
98.5g x Cp x (22.5-221.3 C) = -(0.425g x 4.184 j/gC x 22.5)
-19581.8 g Cp = -40.0095
Cp = 0.00204 J/g °C
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