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Answer :
To find the correct dosage of the drug for a person weighing 150.0 pounds, we'll follow these steps:
1. Convert the person's weight from pounds to kilograms:
- We know the conversion factor between pounds and kilograms is [tex]\(1 \text{ kg} = 2.20 \text{ lb}\)[/tex].
- To convert the weight from pounds to kilograms, we use the formula:
[tex]\[
\text{Weight in kilograms} = \frac{\text{Weight in pounds}}{\text{Conversion factor}}
\][/tex]
- Plug in the values:
[tex]\[
\text{Weight in kilograms} = \frac{150.0 \text{ lb}}{2.20 \text{ lb/kg}} \approx 68.18 \text{ kg}
\][/tex]
2. Calculate the dosage in milligrams based on the body weight in kilograms:
- The dosage required is 1.50 mg per kilogram of body weight.
- We use the formula:
[tex]\[
\text{Dosage in milligrams} = \text{Dosage per kg} \times \text{Weight in kilograms}
\][/tex]
- Substitute the values:
[tex]\[
\text{Dosage in milligrams} = 1.50 \text{ mg/kg} \times 68.18 \text{ kg} \approx 102.27 \text{ mg}
\][/tex]
In conclusion, the person should be given approximately 102 mg of the drug. Therefore, the correct answer from the given options is 102 mg.
1. Convert the person's weight from pounds to kilograms:
- We know the conversion factor between pounds and kilograms is [tex]\(1 \text{ kg} = 2.20 \text{ lb}\)[/tex].
- To convert the weight from pounds to kilograms, we use the formula:
[tex]\[
\text{Weight in kilograms} = \frac{\text{Weight in pounds}}{\text{Conversion factor}}
\][/tex]
- Plug in the values:
[tex]\[
\text{Weight in kilograms} = \frac{150.0 \text{ lb}}{2.20 \text{ lb/kg}} \approx 68.18 \text{ kg}
\][/tex]
2. Calculate the dosage in milligrams based on the body weight in kilograms:
- The dosage required is 1.50 mg per kilogram of body weight.
- We use the formula:
[tex]\[
\text{Dosage in milligrams} = \text{Dosage per kg} \times \text{Weight in kilograms}
\][/tex]
- Substitute the values:
[tex]\[
\text{Dosage in milligrams} = 1.50 \text{ mg/kg} \times 68.18 \text{ kg} \approx 102.27 \text{ mg}
\][/tex]
In conclusion, the person should be given approximately 102 mg of the drug. Therefore, the correct answer from the given options is 102 mg.
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