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Answer :
To estimate the efficacy of Medicine A with 95% confidence, we need to analyze the proportion of subjects who were treated effectively. In this scenario, we're dealing with a single proportion (those treated effectively out of all participants), so the appropriate statistical method to use is the 1-PropZInt.
Here's how you can determine the correct method step-by-step:
Identify the Scenario: You have a single group of subjects (400 total) and you're observing the outcome (160 treated effectively). This is a classic single-proportion situation, where you want to estimate the proportion of success.
Formulate the Problem: You want to calculate the confidence interval for the proportion of subjects effectively treated by Medicine A, based on a sample.
Choose the Correct Method: For a single proportion confidence interval, you use 1-PropZInt (1-Proportion Z-Interval). This method calculates the range of percentages in which the true proportion is expected to fall, with a certain level of confidence (95% in this case).
Calculate the Interval:
- Let [tex]p[/tex] be the sample proportion, calculated as [tex]\frac{160}{400} = 0.4[/tex].
- The formula for a 1-PropZInt is given by the expression:
[tex]\hat{p} \pm Z \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}}[/tex]
where [tex]\hat{p}[/tex] is the sample proportion, [tex]n[/tex] is the sample size, and [tex]Z[/tex] is the Z-score corresponding to the desired confidence level (1.96 for 95% confidence).
Interpret the Results: After performing the computation, you'll get a confidence interval which tells you the range in which the true effectiveness of the medicine likely falls. This provides a statistical backing to the claim of the medicine's efficacy.
Thus, for estimating the efficacy of Medicine A using the results from this study, you should use the 1-PropZInt.
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