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Answer :
To find the potential energy of the bicycle resting at the top of a hill, we can use the formula for potential energy:
[tex]\[ PE = m \cdot g \cdot h \][/tex]
where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (in meters per second squared, m/s²),
- [tex]\( h \)[/tex] is the height of the object above the ground (in meters).
Given:
- The mass [tex]\( m \)[/tex] of the bicycle is 25 kg,
- The height [tex]\( h \)[/tex] of the hill is 3 m,
- The acceleration due to gravity [tex]\( g \)[/tex] is approximately 9.8 m/s².
Plug these values into the formula:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is 735 Joules.
[tex]\[ PE = m \cdot g \cdot h \][/tex]
where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (in meters per second squared, m/s²),
- [tex]\( h \)[/tex] is the height of the object above the ground (in meters).
Given:
- The mass [tex]\( m \)[/tex] of the bicycle is 25 kg,
- The height [tex]\( h \)[/tex] of the hill is 3 m,
- The acceleration due to gravity [tex]\( g \)[/tex] is approximately 9.8 m/s².
Plug these values into the formula:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is 735 Joules.
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