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A 8.00-kg mass moving east at 15.0 m/s on a frictionless horizontal surface collides with a 10.0-kg mass that is initially at rest. After the collision, the 8.00-kg mass moves south at 4.00 m/s.

(a) What is the velocity of the 10.0-kg mass after the collision?

Answer :

Final answer:

The final velocity of the 10-kg mass after collision can be calculated using the principles of conservation of momentum and considering the momentum separately in each direction.

Explanation:

In the field of Physics, calculations related to collisions such as this are typically solved using the principles of conservation of momentum. Momentum is defined as the product of an object's mass and its velocity. The total momentum of a closed system, like the two objects in this collision, remains constant before and after the collision.

The initial momentum of the 8.00-kg mass is its mass times its velocity (8.00 kg * 15 m/s = 120 kg.m/s, towards the east) while the 10.0-kg mass at rest has an initial momentum of zero. After the collision, the 8.00-kg mass has a momentum of 32 kg.m/s, towards the south.

Now we can calculate the final momentum of the 10.0-kg mass. Using vector mathematics to consider the conservation of momentum in each direction separately, we can compute the final velocity, which is the missing link in your question. Do note that such a computation requires careful attention to the direction of each vector.

Learn more about Conservation of Momentum here:

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