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1. Two genes—pointiness of chin and pointiness of nose—have the following alleles:

- P = pointy chin
- p = round chin
- N = round nose
- n = pointy nose

A man with a pointy chin and pointy nose mates with a woman with a round chin and round nose and produces a child with a pointy chin and round nose. What are all the possible genotypes for this child?

2. In humans, short fingers (F) and widow's peak (W) are dominant over long fingers (f) and a straight hairline (w). A heterozygote for both genes reproduces with a similar heterozygote. What is the chance of any one child having the same phenotype as the parents?

Answer :

The possible genotypes for the child are: Pn and pn from the descriptions in the question.

What are the possible genes?

To determine this, we can use a Punnett square. The man has the genotype PPnn (pointy chin and pointy nose), and the woman has the genotype ppNN (round chin and round nose).

The offspring genotype possibilities are PNn, PnN, Pnn, and pnn. However, we are told that the child has a pointy chin and a round nose, so the only possible genotypes for this phenotype are Pn and pn.

Therefore, the child could have the genotype Pn (pointy chin, round nose) or pn (round chin, pointy nose).

Learn more about genes:https://brainly.com/question/8832859

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