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Answer :
We want to find the value of
[tex]$$
\log_4 128.
$$[/tex]
To do this, we use the change-of-base formula:
[tex]$$
\log_4 128 = \frac{\log 128}{\log 4}.
$$[/tex]
We are given that
[tex]$$
\log 128 \approx 2.1 \quad \text{and} \quad \log 4 \approx 0.6.
$$[/tex]
Substitute these values into the formula:
[tex]$$
\log_4 128 \approx \frac{2.1}{0.6}.
$$[/tex]
Now, compute the division:
[tex]$$
\frac{2.1}{0.6} \approx 3.5.
$$[/tex]
Thus, the approximate value is:
[tex]$$
\log_4 128 \approx 3.5.
$$[/tex]
[tex]$$
\log_4 128.
$$[/tex]
To do this, we use the change-of-base formula:
[tex]$$
\log_4 128 = \frac{\log 128}{\log 4}.
$$[/tex]
We are given that
[tex]$$
\log 128 \approx 2.1 \quad \text{and} \quad \log 4 \approx 0.6.
$$[/tex]
Substitute these values into the formula:
[tex]$$
\log_4 128 \approx \frac{2.1}{0.6}.
$$[/tex]
Now, compute the division:
[tex]$$
\frac{2.1}{0.6} \approx 3.5.
$$[/tex]
Thus, the approximate value is:
[tex]$$
\log_4 128 \approx 3.5.
$$[/tex]
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