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Select the correct answer from each drop-down menu.

1. If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a chance that ___ of the offspring will be heterozygous.

[tex]\[
\begin{tabular}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{tabular}
\][/tex]

2. If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is ___.

[tex]\[
\begin{tabular}{|c|c|c|}
\hline & W & w \\
\hline W & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{tabular}
\][/tex]

Answer :

To solve the genetic probability question, let's break down each scenario step by step:

1. Heterozygous Male (Ww) x Homozygous Recessive Female (ww):

- When we mate a heterozygous male (Ww) with a homozygous recessive female (ww), we can create a Punnett square to determine the possible offspring.
- The male (Ww) has alleles W and w.
- The female (ww) has alleles w and w.

The Punnett square looks like this:

[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\][/tex]

- From this, you can see the possible offspring genotypes: Ww, ww, Ww, ww.
- Among these, two out of the four possible combinations are heterozygous (Ww).
- This means there is a 2 out of 4 chance, or 50%, for the offspring to be heterozygous.

2. Heterozygous Male (Ww) x Homozygous Dominant Female (WW):

- Now, we're considering a heterozygous male (Ww) crossed with a homozygous dominant female (WW).
- The male (Ww) has alleles W and w.
- The female (WW) has alleles W and W.

The Punnett square looks like this:

[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline W & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{array}
\][/tex]

- From this setup, the possible offspring genotypes are WW, Ww, WW, Ww.
- In this case, none of the offspring are homozygous recessive (ww), since all have at least one dominant allele (W).
- Therefore, the probability of having a homozygous recessive offspring is 0 out of 4, which is 0%.

In summary:
- There is a 50% probability that the offspring from the first mating are heterozygous (Ww).
- There is a 0% probability of having a homozygous recessive (ww) offspring from the second mating.

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