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Answer :
Answer:
0.917 seconds
Explanation:
Given that,
length of a snake is 2.97 m
The speed of the snake is 3.24 m/s
The acceleration of the snake is 3.09 m/s²
We need to find the time taken by the snake to reach its top speed. Let t is the time.
Speed = distance/time
Here, distance = length of the snake
[tex]t=\dfrac{d}{v}\\\\t=\dfrac{2.97\ m}{3.24\ m/s}\\\\t=0.917\ s[/tex]
Hence, the time taken by the snake to reach its top speed is 0.917 seconds.
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Final answer:
It takes the black mamba approximately 1.05 seconds to reach its top speed when accelerating from rest at 3.09 m/s^2.
Explanation:
To solve this problem we'll have to use some basic physics. Specifically, we can use the formula for time given acceleration and final velocity, which is: time = final velocity / acceleration.
Here, the final velocity is the top speed of the snake, which is 3.24 m/s. The acceleration is given as 3.09 m/s^2. Plugging these values into the formula gives us: time = 3.24 m/s / 3.09 m/s^2 = 1.04854368932 seconds.
Therefore, it takes the black mamba approximately 1.05 seconds to reach its top speed when accelerating from rest at 3.09 m/s^2.
Learn more about acceleration here:
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