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A 25 kg turkey is fired from a 1.2 x [tex]10^3[/tex] kg turkey launcher. If the horizontal velocity of the turkey is 245 m/s east, what is the recoil velocity of the launcher?

A. 9.38 m/s
B. 7325 m/s
C. 4925 m/s
D. 5.1 m/s

Answer :

The recoil velocity of the launcher is 5.1 m/s.

option D.

What is the recoil velocity of the launcher?

To calculate the recoil velocity of the launcher, we can use the law of conservation of momentum.

According to this law, the total momentum of the system (turkey + launcher) before the launch is equal to the total momentum after the launch.

initial momentum of the turkey = final momentum of the launcher

( 25 kg x 245 m/s ) = 1,200 kg (v)

where;

  • v is the recoil velocity of the launcher

v = ( 6125 kgm/s) / ( 1,200 kg )

v = 5.1 m/s

Learn more about recoil velocity here: https://brainly.com/question/19360264

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