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Answer :
We are given the variance of the data as
$$
\sigma^2 = 366.3.
$$
The standard deviation, $\sigma$, is defined as the square root of the variance. Therefore, we calculate
$$
\sigma = \sqrt{\sigma^2} = \sqrt{366.3}.
$$
Evaluating the square root gives
$$
\sigma \approx 19.138965489283898.
$$
Thus, the standard deviation of the data is approximately
$$
\boxed{19.14}.
$$
$$
\sigma^2 = 366.3.
$$
The standard deviation, $\sigma$, is defined as the square root of the variance. Therefore, we calculate
$$
\sigma = \sqrt{\sigma^2} = \sqrt{366.3}.
$$
Evaluating the square root gives
$$
\sigma \approx 19.138965489283898.
$$
Thus, the standard deviation of the data is approximately
$$
\boxed{19.14}.
$$
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