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Answer :
We start with an initial area of moss of [tex]$11 \text{ cm}^2$[/tex]. Every month, the area multiplies by a factor of [tex]$1.5$[/tex]. After [tex]$6$[/tex] months, the total multiplication factor is
[tex]$$1.5^6.$$[/tex]
Calculating the multiplication factor:
[tex]$$1.5^6 = 11.390625.$$[/tex]
Thus, the final area after [tex]$6$[/tex] months is given by
[tex]$$\text{Final Area} = 11 \times 11.390625 = 125.296875 \text{ cm}^2.$$[/tex]
Rounding to one decimal place, the area is approximately [tex]$125.3 \text{ cm}^2$[/tex].
Therefore, the correct answer is:
A. [tex]$\quad 125.3 cm^2$[/tex]
[tex]$$1.5^6.$$[/tex]
Calculating the multiplication factor:
[tex]$$1.5^6 = 11.390625.$$[/tex]
Thus, the final area after [tex]$6$[/tex] months is given by
[tex]$$\text{Final Area} = 11 \times 11.390625 = 125.296875 \text{ cm}^2.$$[/tex]
Rounding to one decimal place, the area is approximately [tex]$125.3 \text{ cm}^2$[/tex].
Therefore, the correct answer is:
A. [tex]$\quad 125.3 cm^2$[/tex]
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