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A potter was pushing a patient from the ward with a wheelchair with back wheels having a diameter of 60 cm to an ambulance parked 50 m away from the ward.

4.1. How many times will the back wheels of the wheelchair turn in 50 m?

4.2. Calculate the circumference of the back wheels of the wheelchair in meters.

4.3. If the radius of the small wheel is 8 cm, calculate its circumference in meters.

4.4. How many times does the small wheel turn in 50 m?

Answer :

  • The back wheels of the wheelchair will turn approximately 26.18 times in 50 meters.
  • The circumference of the back wheels of the wheelchair in meters is 0.6 π meters.
  • The circumference of the small wheel in meters is 0.16 π meters.
  • The small wheel turns approximately 98.98 times in 50 meters.

Circular motion problem

To find the number of times the back wheels of the wheelchair will turn in 50 m, we need to find the distance covered by one full revolution of the back wheel. The circumference of the back wheel is equal to the distance covered by one full revolution.

  • Circumference = π x diameter
  • Circumference = π x 60 cm
  • Circumference = 0.6 π meters

The distance covered by one full revolution of the back wheel is 0.6 π meters. To cover a distance of 50 meters, the back wheel needs to turn:

50 meters / 0.6 π meters per revolution ≈ 26.18 revolutions

The circumference of the back wheels of the wheelchair in meters is:

  • Circumference = π x diameter
  • Circumference = π x 60 cm / 100
  • Circumference = 0.6 π meters

The radius of the small wheel is given as 8 cm. The circumference of the small wheel can be calculated as:

Circumference = 2πr

Circumference = 2π x 8 cm / 100

Circumference = 0.16 π meters

To find the number of times the small wheel turns in 50 m, we need to find the distance covered by one full revolution of the small wheel. The circumference of the small wheel is equal to the distance covered by one full revolution.

The distance covered by one full revolution of the small wheel is 0.16 π meters. To cover a distance of 50 meters, the small wheel needs to turn:

50 meters / 0.16 π meters per revolution ≈ 98.98 revolutions

More on circular motion problems can be found here: https://brainly.com/question/29312275

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Rewritten by : Barada