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Answer :
Answer:
Step-by-step explanation:
To find the maximum width of an aircraft seat that will accommodate 98% of all adult women, we need to determine the corresponding z-score for the 98th percentile of the normal distribution.
First, we find the z-score corresponding to the 98th percentile using a standard normal distribution table or calculator. The z-score for the 98th percentile is approximately 2.05.
Next, we use the z-score formula to find the corresponding value in the original distribution:
z = (x - μ) / σ
Solving for x (the maximum width of the aircraft seat):
x = z * σ + μ
Substituting the values given:
x = 2.05 * 4.36 + 37.6
x ≈ 45.98
Therefore, the maximum width of an aircraft seat that will accommodate 98% of all adult women is approximately 46 cm (rounded to one decimal place).
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