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N₂ + 3H₂ → 2NH₃

How many moles of NH₃ form when 8.00 mol of H₂ react?

A. 4.00 mol NH₃
B. 2.67 mol NH₃
C. 12.0 mol NH₃
D. 5.33 mol NH₃

Answer :

Final answer:

To determine the amount of NH3 formed when 8.00 mol H2 reacts, we can use the stoichiometry of the reaction. The correct answer is 5.33 mol NH3.


Explanation:

To determine the number of moles of NH3 formed when 8.00 mol H2 reacts, we need to use the balanced chemical equation and the stoichiometry of the reaction.

The balanced chemical equation is N2 + 3H2 -> 2NH3.

From the equation, we can see that for every 3 moles of H2, 2 moles of NH3 are formed. Therefore, since there are 8.00 mol H2, we can calculate:

(8.00 mol H2) x (2 mol NH3/3 mol H2) = 5.33 mol NH3

Therefore, the correct answer is Option D. 5.33 mol NH3.


Learn more about stoichiometry here:

https://brainly.com/question/30218216


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