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Josiah invests [tex]\$360[/tex] into an account that accrues 3\% interest annually. Assuming no deposits or withdrawals are made, which equation represents the amount of money in Josiah's account, [tex]y[/tex], after [tex]x[/tex] years?

A. [tex]y = 360(1.3)^x[/tex]
B. [tex]y = 360(0.3)^x[/tex]
C. [tex]y = 360(0.03)^x[/tex]
D. [tex]y = 360(1.03)^x[/tex]

Answer :

We start by identifying the key parts of the problem:

1. The principal amount is \[tex]$360.
2. The annual interest rate is 3%, which as a decimal is $[/tex]0.03[tex]$.
3. When interest is compounded annually, the formula to calculate the account balance after $[/tex]x[tex]$ years is

$[/tex][tex]$
y = \text{principal} \times (1 + \text{interest rate})^x.
$[/tex][tex]$

Substitute the given values into the formula:

$[/tex][tex]$
y = 360 \times (1 + 0.03)^x.
$[/tex][tex]$

Simplify the expression inside the parentheses:

$[/tex][tex]$
1 + 0.03 = 1.03.
$[/tex][tex]$

Thus, the equation becomes

$[/tex][tex]$
y = 360 \times (1.03)^x.
$[/tex][tex]$

This is the correct expression for the amount of money in Josiah's account after $[/tex]x$ years.

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