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530 mL of CO gas is at a pressure of 1.2 atm and a temperature of 17ºC. What is the volume of the gas at 0ºC and 1 atm?

Answer :

Answer:

598.74 mL

Explanation:

Using Ideal gas equation for same mole of gas as

[tex] \frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}[/tex]

Given ,

V₁ = 530 mL

V₂ = ?

P₁ = 1.2 atm

P₂ = 1 atm

T₁ = 17 ºC

T₂ = 0 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (17 + 273.15) K = 290.15 K

T₂ = (0 + 273.15) K = 273.15 K

Using above equation as:

[tex] \frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}[/tex]

[tex] \frac {{1.2}\times {530}}{290.15}=\frac {{1}\times {V_2}}{273.15}[/tex]

Solving for V₂ , we get:

V₂ = 598.74 mL

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