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Answer :
To find the molarity of a solution formed by dissolving 97.7 grams of LiBr (Lithium Bromide) in enough water to make 750.0 milliliters (mL) of solution, follow these steps:
1. Calculate the Molar Mass of LiBr:
Lithium (Li) has an atomic mass of approximately 6.94 g/mol, and Bromine (Br) has an atomic mass of approximately 79.90 g/mol.
Molar mass of LiBr = Molar mass of Li + Molar mass of Br
= 6.94 g/mol + 79.90 g/mol
= 86.84 g/mol
2. Convert the Volume from mL to Liters:
Since molarity is expressed in moles per liter, convert the given volume from milliliters to liters.
Volume in liters = 750.0 mL × (1 L / 1000 mL)
= 0.750 L
3. Calculate the Moles of LiBr:
Use the formula: Moles = Mass / Molar Mass
Moles of LiBr = 97.7 g / 86.84 g/mol
= 1.125 moles (approximately)
4. Calculate the Molarity:
Molarity (M) is calculated using the formula: Molarity = Moles of solute / Volume of solution in liters
Molarity = 1.125 moles / 0.750 L
= 1.50 M
Thus, the molarity of the solution is 1.50 M.
1. Calculate the Molar Mass of LiBr:
Lithium (Li) has an atomic mass of approximately 6.94 g/mol, and Bromine (Br) has an atomic mass of approximately 79.90 g/mol.
Molar mass of LiBr = Molar mass of Li + Molar mass of Br
= 6.94 g/mol + 79.90 g/mol
= 86.84 g/mol
2. Convert the Volume from mL to Liters:
Since molarity is expressed in moles per liter, convert the given volume from milliliters to liters.
Volume in liters = 750.0 mL × (1 L / 1000 mL)
= 0.750 L
3. Calculate the Moles of LiBr:
Use the formula: Moles = Mass / Molar Mass
Moles of LiBr = 97.7 g / 86.84 g/mol
= 1.125 moles (approximately)
4. Calculate the Molarity:
Molarity (M) is calculated using the formula: Molarity = Moles of solute / Volume of solution in liters
Molarity = 1.125 moles / 0.750 L
= 1.50 M
Thus, the molarity of the solution is 1.50 M.
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