We appreciate your visit to After scoring a touchdown a 103 kg wide receiver celebrates by leaping 1 60 m off the ground How much work was done by the. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The work done by the wide receiver is 1615.04 Joules.
Explanation:
The amount of work done by the wide receiver can be calculated using the equation:
Work = force × distance
In this case, the force acting on the receiver is equal to his weight, which is the product of his mass (103 kg) and the acceleration due to gravity (9.8 m/s²).
So, the force = mass × acceleration due to gravity = 103 kg × 9.8 m/s² = 1009.4 kg·m/s².
The distance the receiver jumps is 1.60 m.
Therefore, the work done by the wide receiver in the celebration is:
Work = force × distance = 1009.4 kg·m/s² × 1.60 m = 1615.04 kg·m²/s² or 1615.04 Joules.
Learn more about Work and Energy here:
https://brainly.com/question/16987255
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