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Answer :
Sure! Let's go through the question step by step.
Scenario 1: Heterozygous Male (Ww) with Homozygous Recessive Female (ww)
1. We have a heterozygous male with the genotype Ww and a homozygous recessive female with the genotype ww.
2. To find the possible genotypes of their offspring, we set up a Punnett square:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\][/tex]
3. The offspring can be either Ww (heterozygous) or ww (homozygous recessive). From the Punnett square, we see two possibilities for Ww and two for ww.
4. Therefore, the probability that an offspring will be heterozygous (Ww) is 2 out of 4 (or 50%).
Scenario 2: Heterozygous (WW) with Homozygous Dominant (WW)
1. In this scenario, we incorrectly have stated a "heterozygous (WW)"—let's correct that to "heterozygous (Ww)" for this analysis as the question context earlier suggests.
2. The homozygous dominant individual has the genotype WW.
3. Let's set up a Punnett square for Ww crossed with WW:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & W \\
\hline W & WW & WW \\
\hline w & Ww & Ww \\
\hline
\end{array}
\][/tex]
4. The offspring are all either WW or Ww. There are no recessive (ww) offspring.
5. Therefore, the probability of having a homozygous recessive offspring (ww) is 0%.
These probabilities reflect the numerical results given: a 50% chance of heterozygous (Ww) offspring in the first scenario and 0% chance of homozygous recessive (ww) offspring in the second scenario.
Scenario 1: Heterozygous Male (Ww) with Homozygous Recessive Female (ww)
1. We have a heterozygous male with the genotype Ww and a homozygous recessive female with the genotype ww.
2. To find the possible genotypes of their offspring, we set up a Punnett square:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\][/tex]
3. The offspring can be either Ww (heterozygous) or ww (homozygous recessive). From the Punnett square, we see two possibilities for Ww and two for ww.
4. Therefore, the probability that an offspring will be heterozygous (Ww) is 2 out of 4 (or 50%).
Scenario 2: Heterozygous (WW) with Homozygous Dominant (WW)
1. In this scenario, we incorrectly have stated a "heterozygous (WW)"—let's correct that to "heterozygous (Ww)" for this analysis as the question context earlier suggests.
2. The homozygous dominant individual has the genotype WW.
3. Let's set up a Punnett square for Ww crossed with WW:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & W \\
\hline W & WW & WW \\
\hline w & Ww & Ww \\
\hline
\end{array}
\][/tex]
4. The offspring are all either WW or Ww. There are no recessive (ww) offspring.
5. Therefore, the probability of having a homozygous recessive offspring (ww) is 0%.
These probabilities reflect the numerical results given: a 50% chance of heterozygous (Ww) offspring in the first scenario and 0% chance of homozygous recessive (ww) offspring in the second scenario.
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