We appreciate your visit to Under the efforts of the College Algebra second period class a pile of homework problems decreased exponentially It decreased from 1400 to 1000 problems in. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Step-by-step explanation:
Well it is simple.If he was able to solve 400 problems in just 25 ' then how long would it take him to solve 100(1/4 of 400)?It would take him 6.25' to solve 100 problems(1/4 of 25).So if he had to do another 500 (because 1000 -500=500) it would take him 31.25' (5*6.25) to complete them.If you have any further questions please contact me.
Yours sincerely,
Manos
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