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What is the velocity of a 900 kg car initially moving at 30.0 m/s, just after it hits a 165 kg deer initially running at 13.0 m/s in the same direction? Assume the deer remains on the car.
To solve this question, we will apply the law of conservation of energy as shown
m1u1+m2u2 = (m1+m2)v
m1 is the mass of the car = 900kg
u1 is the initial velocity of the car = 30m/s
m2 is the mass of the deer = 165kg
u2 is the initial velocity is the deer = 13m/s
v is the common velocity after collision
Substitute the given values into the formula as shown;
900(30)+165(13) = (900+165)v
27000+2145 = 1065v
29145 = 1065v
v = 29145/1065
v = 27.37m/s
Since both the car and deer have the same velocity after collision, hence the velocity of the car after hitting the deer is 27.37m/s
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