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Answer :
Based on the calculations, the required pressure in this oil is equal to [tex]54.9 \times 10^6 \;N/m^2[/tex]
Given the following data:
Force = 38.8 kN.
Diameter = 30 mm to m = 0.03 m.
What is pressure?
Pressure can be defined as a measure of the force exerted per unit area of an object or physical body. Thus, it is usually measured in Newton per meter square and calculated by using this formula:
[tex]P = \frac{F}{A}[/tex]
Where:
- P is the pressure.
- F is the force.
- A is the area.
For the area:
[tex]A =\frac{\pi d^2}{4} \\\\A=\frac{3.142 \times 0.03^2 }{4} \\\\A=0.000707\;m^2[/tex]
Now, we can determine the pressure:
[tex]P=\frac{38.8 \times 10^3}{0.000707}[/tex]
[tex]P = 54.9 \times 10^6 \;N/m^2[/tex]
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Answer:
Pressure in the oil is 54.89 Mpa
Explanation:
Pressure is the ration of force applied to the perpendicular area. Pressure is uniform and perpendicular to surface.
Step1
Given:
Diameter of the piston is 30 mm.
Force exert is 38.8 kN.
Calculation:
Step2
Expression for pressure in the oil is expressed as follows:
[tex]P=\frac{F}{A}[/tex]
Here, P is the pressure, A is the normal surface area and F is the exerted force on the piston.
Substitute the values in the above equation as follows:
[tex]P=\frac{F}{\frac{\pi}{4}d^{2}}[/tex]
[tex]P=\frac{38.8\times1000}{\frac{\pi}{4} ((30mm)(\frac{1m}{1000mm}))^{2} }[/tex]
[tex]P = 54.89\times10^{6}[/tex] pa.
Or,
P = 54.89 Mpa.
Thus, the pressure in the oil is 54.89 Mpa.
