Answer :

To solve the problem of finding how many grams of [tex]\( H_2SO_4 \)[/tex] are in 135 mL of a 0.250 M solution, you can follow these steps:

1. Understand Molarity: Molarity (M) is defined as the number of moles of solute per liter of solution. In this case, the solution is 0.250 M [tex]\( H_2SO_4 \)[/tex]. This means there are 0.250 moles of [tex]\( H_2SO_4 \)[/tex] in one liter of this solution.

2. Convert Volume to Liters: The volume of the solution is 135 mL. Since molarity is in terms of liters, you need to convert milliliters to liters.

[tex]\[
135 \, \text{mL} = \frac{135}{1000} = 0.135 \, \text{L}
\][/tex]

3. Calculate Moles of [tex]\( H_2SO_4 \)[/tex]: Use the molarity and the volume in liters to find the number of moles of [tex]\( H_2SO_4 \)[/tex] in the solution.

[tex]\[
\text{moles of } H_2SO_4 = \text{Molarity} \times \text{Volume in Liters} = 0.250 \, \text{M} \times 0.135 \, \text{L} = 0.03375 \, \text{moles}
\][/tex]

4. Find Molar Mass of [tex]\( H_2SO_4 \)[/tex]: The molar mass of [tex]\( H_2SO_4 \)[/tex] is approximately 98.08 g/mol.

5. Calculate Mass of [tex]\( H_2SO_4 \)[/tex]: Finally, use the number of moles and the molar mass to find the mass in grams.

[tex]\[
\text{mass in grams} = \text{moles} \times \text{molar mass} = 0.03375 \, \text{moles} \times 98.08 \, \text{g/mol} = 3.3102 \, \text{grams}
\][/tex]

Therefore, there are approximately 3.3102 grams of [tex]\( H_2SO_4 \)[/tex] in 135 mL of a 0.250 M solution.

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