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Answer :
The force of the bat on the ball is 339486.67 lb.
Mass of baseball = 0.32 lb Initial velocity of baseball = 94 mph = (94 × 5280) / 3600 = 138.67 ft/s Final velocity of baseball = 126 mph = (126 × 5280) / 3600 = 184.8 ft/s Time taken by baseball to come to rest = 0.0015 s Force of the bat on the ball = Formulae to be used: Impulse = Change in momentum Force × time = Change in momentum. Momentum of the ball before being hit by the bat, p1 = mv1 = 0.32 × 32.17 × 138.67= 1453.25 lb ft/s Momentum of the ball after being hit by the bat, p2 = mv2 = 0.32 × 32.17 × 184.8= 1962.48 lb ft/s Change in momentum, ∆p = p2 – p1= 1962.48 – 1453.25= 509.23 lb ft/s Impulse = Change in momentum = ∆p= 509.23 lb ft/s Force × time = ∆p Force = ∆p / time = 509.23 / 0.0015= 339486.67 lb
The force of the bat on the ball is 339486.67 lb.
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