We appreciate your visit to You are helping with some repairs at home You drop a hammer and it hits the floor at a speed of 8 feet per second. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
To solve the problem of how far above the ground the hammer was when it was dropped, we need to use the formula for the velocity of an object in free fall:
[tex]\[ v = \sqrt{2gh} \][/tex]
where:
- [tex]\( v \)[/tex] is the velocity of the object when it hits the ground,
- [tex]\( g \)[/tex] is the acceleration due to gravity,
- [tex]\( h \)[/tex] is the height from which the object was dropped.
We are given:
- [tex]\( v = 8 \)[/tex] feet per second (the speed of the hammer when it hits the floor),
- [tex]\( g = 32 \)[/tex] feet/second[tex]\(^2\)[/tex] (the acceleration due to gravity).
Our goal is to find [tex]\( h \)[/tex], the height from which the hammer was dropped. We can rearrange the formula to solve for [tex]\( h \)[/tex]:
[tex]\[ h = \frac{v^2}{2g} \][/tex]
Let's calculate the height [tex]\( h \)[/tex]:
1. Square the velocity: [tex]\( v^2 = 8^2 = 64 \)[/tex].
2. Multiply the gravity by 2: [tex]\( 2g = 2 \times 32 = 64 \)[/tex].
3. Divide the squared velocity by twice the gravity:
[tex]\[ h = \frac{64}{64} = 1.0 \][/tex]
Therefore, the height from which the hammer was dropped is 1.0 foot. The correct answer is:
C. 1.0 foot
[tex]\[ v = \sqrt{2gh} \][/tex]
where:
- [tex]\( v \)[/tex] is the velocity of the object when it hits the ground,
- [tex]\( g \)[/tex] is the acceleration due to gravity,
- [tex]\( h \)[/tex] is the height from which the object was dropped.
We are given:
- [tex]\( v = 8 \)[/tex] feet per second (the speed of the hammer when it hits the floor),
- [tex]\( g = 32 \)[/tex] feet/second[tex]\(^2\)[/tex] (the acceleration due to gravity).
Our goal is to find [tex]\( h \)[/tex], the height from which the hammer was dropped. We can rearrange the formula to solve for [tex]\( h \)[/tex]:
[tex]\[ h = \frac{v^2}{2g} \][/tex]
Let's calculate the height [tex]\( h \)[/tex]:
1. Square the velocity: [tex]\( v^2 = 8^2 = 64 \)[/tex].
2. Multiply the gravity by 2: [tex]\( 2g = 2 \times 32 = 64 \)[/tex].
3. Divide the squared velocity by twice the gravity:
[tex]\[ h = \frac{64}{64} = 1.0 \][/tex]
Therefore, the height from which the hammer was dropped is 1.0 foot. The correct answer is:
C. 1.0 foot
Thanks for taking the time to read You are helping with some repairs at home You drop a hammer and it hits the floor at a speed of 8 feet per second. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
