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Answer :
To find the potential energy of a bicycle resting at the top of a hill, we use the formula for gravitational potential energy:
[tex]\[
PE = m \times g \times h
\][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the object (bicycle),
- [tex]\( g \)[/tex] is the acceleration due to gravity, and
- [tex]\( h \)[/tex] is the height of the hill.
For this problem:
- The mass [tex]\( m \)[/tex] is 25 kg,
- The acceleration due to gravity [tex]\( g \)[/tex] is approximately 9.8 m/s², and
- The height [tex]\( h \)[/tex] is 3 meters.
Let's plug these values into the formula:
1. Multiply the mass and the height:
[tex]\[
m \times h = 25 \, \text{kg} \times 3 \, \text{m} = 75 \, \text{kg}\cdot\text{m}
\][/tex]
2. Now multiply this result by the acceleration due to gravity:
[tex]\[
PE = 75 \, \text{kg}\cdot\text{m} \times 9.8 \, \text{m/s}^2 = 735 \, \text{J}
\][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is 735 joules (J). So, the correct answer is 735 J.
[tex]\[
PE = m \times g \times h
\][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the object (bicycle),
- [tex]\( g \)[/tex] is the acceleration due to gravity, and
- [tex]\( h \)[/tex] is the height of the hill.
For this problem:
- The mass [tex]\( m \)[/tex] is 25 kg,
- The acceleration due to gravity [tex]\( g \)[/tex] is approximately 9.8 m/s², and
- The height [tex]\( h \)[/tex] is 3 meters.
Let's plug these values into the formula:
1. Multiply the mass and the height:
[tex]\[
m \times h = 25 \, \text{kg} \times 3 \, \text{m} = 75 \, \text{kg}\cdot\text{m}
\][/tex]
2. Now multiply this result by the acceleration due to gravity:
[tex]\[
PE = 75 \, \text{kg}\cdot\text{m} \times 9.8 \, \text{m/s}^2 = 735 \, \text{J}
\][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is 735 joules (J). So, the correct answer is 735 J.
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