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What is the logarithmic form of [tex]$13^2=169$[/tex]?

A. [tex]\log _{13} 169=2[/tex]
B. [tex]\log _{13} 2=169[/tex]
C. [tex]\log _2 13=169[/tex]
D. [tex]\log _2 169=13[/tex]

Answer :

To express the equation [tex]\(13^2 = 169\)[/tex] in logarithmic form, we need to remember the fundamental relationship between exponents and logarithms. The exponential equation [tex]\(a^b = c\)[/tex] can be rewritten in logarithmic form as [tex]\(\log_a c = b\)[/tex].

In the equation [tex]\(13^2 = 169\)[/tex]:

- The base [tex]\(a\)[/tex] is 13.
- The exponent [tex]\(b\)[/tex] is 2.
- The result [tex]\(c\)[/tex] is 169.

Using the formula, we can write the logarithmic form as [tex]\(\log_{13} 169 = 2\)[/tex].

So, the correct choice from the given options is:

[tex]\(\log_{13} 169 = 2\)[/tex]

Thanks for taking the time to read What is the logarithmic form of tex 13 2 169 tex A tex log 13 169 2 tex B tex log 13 2 169 tex. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

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