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Answer :
To find the potential energy of a 25 kg bicycle at the top of a hill 3 meters high, you can use the formula for gravitational potential energy:
[tex]\[ \text{Potential Energy (PE)} = m \times g \times h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity, which is approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex],
- [tex]\( h \)[/tex] is the height (in meters).
Given:
- [tex]\( m = 25 \, \text{kg} \)[/tex],
- [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex],
- [tex]\( h = 3 \, \text{m} \)[/tex].
Substituting these values into the formula gives:
[tex]\[ \text{PE} = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ \text{PE} = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the bicycle is 735 Joules. So, the correct answer is 735 J.
[tex]\[ \text{Potential Energy (PE)} = m \times g \times h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity, which is approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex],
- [tex]\( h \)[/tex] is the height (in meters).
Given:
- [tex]\( m = 25 \, \text{kg} \)[/tex],
- [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex],
- [tex]\( h = 3 \, \text{m} \)[/tex].
Substituting these values into the formula gives:
[tex]\[ \text{PE} = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ \text{PE} = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the bicycle is 735 Joules. So, the correct answer is 735 J.
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