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A 185-kg object and a 485-kg object are separated by 3.50 m.

(a) Find the magnitude of the net gravitational force exerted by these objects on a 52.0-kg object placed midway between them.

(b) At what position (other than an infinitely remote one) can the 52.0-kg object be placed so as to experience a net force of zero from the other two objects?

Answer :

Final answer:

The question pertains to gravitational forces among three bodies. In order to solve it, one needs to use the universal law of gravitation. Considering these principles, the net gravitational force on the 52-kg object placed midway between the two heavier objects is effectively zero, and the object experiences zero net force when it is closer to the lighter object.

Explanation:

This is a problem related to gravitational forces between three objects. For both parts of the question, we'll be using the universal law of gravitation, which states that the force between two objects is equal to the gravitational constant times the mass of each object, divided by the square of the distance between the objects' centers.

(a) To calculate the net gravitational force, we sum the individual forces from the 185-kg and 485-kg objects on the 52-kg object. Because these forces are in opposite directions, we subtract them. Using the universal law of gravitation, you will find that the net force on the 52-kg object is effectively zero.

(b) For the 52-kg object to experience zero net force, it must be placed closer to the 185-kg object. We can set up an equation where the gravitational force from the 185-kg object equals the gravitational force from the 485-kg object and solve for distance. From this, you can calculate the exact position required.

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