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At the gym, Jasper was able to bench press 224 pounds, which was [tex]\frac{7}{8}[/tex] of the weight that Balin was able to bench press.

Which shows the correct equation and value of [tex]x[/tex], the weight that Balin could bench press?

A. [tex]\frac{7}{8} x = 224 ; x = 196[/tex] pounds
B. [tex]\frac{7}{8} x = 224 ; x = 256[/tex] pounds
C. [tex]\frac{7}{8} = \frac{x}{224} ; x = 196[/tex] pounds
D. [tex]\frac{7}{8} = \frac{x}{224} ; x = 256[/tex] pounds

Answer :

To solve this problem, we need to find out the weight that Balin could bench press, given that Jasper was able to lift [tex]\( \frac{7}{8} \)[/tex] of that weight, which is 224 pounds.

Let's denote the weight Balin can bench press as [tex]\( x \)[/tex].

The equation that represents this scenario is:
[tex]\[ \frac{7}{8} \times x = 224 \][/tex]

To find [tex]\( x \)[/tex], we need to solve the equation for [tex]\( x \)[/tex]. Here's how we do it step-by-step:

1. Start with the equation:
[tex]\[ \frac{7}{8} \times x = 224 \][/tex]

2. To isolate [tex]\( x \)[/tex], divide both sides of the equation by [tex]\( \frac{7}{8} \)[/tex]:
[tex]\[ x = \frac{224}{\frac{7}{8}} \][/tex]

3. Dividing by a fraction is the same as multiplying by its reciprocal. The reciprocal of [tex]\( \frac{7}{8} \)[/tex] is [tex]\( \frac{8}{7} \)[/tex].

4. So, multiply 224 by the reciprocal of [tex]\( \frac{7}{8} \)[/tex]:
[tex]\[ x = 224 \times \frac{8}{7} \][/tex]

5. Perform the multiplication:
[tex]\[ x = \frac{224 \times 8}{7} \][/tex]

6. Calculate the result:
[tex]\[ x = 256 \][/tex]

Therefore, the weight that Balin could bench press is 256 pounds. The correct equation and value are [tex]\(\frac{7}{8} x = 224\)[/tex] and [tex]\(x = 256\)[/tex] pounds.

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