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Eric is building a storage box for his nephews. The box dimensions are 42 inches long, 24 inches deep, and 20 inches tall. He plans to cover the entire outside of the box with three coats of a clear coat protective finish.

If each can of finish covers about 27.5 square feet, what is the minimum number of cans of finish needed for the job?

Explain how you found your answer.

Answer :

2 cans of finish are required for completing one box as planned by Eric

We have,

Length =42 inches

Breadth=24 inches

Height= 20 inches

Area covered by each can of finish =27.5 square feet.

Number of coats required= 3.

1 square inch = .00694 square foot.

First, we need to find the total surface area of the cuboid.

TSA of cuboid= 2(lb+lh+bh)= 2(1008+840+480)=2322 square inches

=16.125 square feet

3 such coats are needed, so the total area is 48.375 square feet

Cans required = Total area/area covered by finish in one can = 48.375/27.5=1.76

]Therefore a minimum of 2 cans on average is required for one box.

For reference ,

brainly.com/question/31319462

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