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Answer :
The normal force is the centripetal force which is given by:
[tex]F=\frac{mv^2}{r}[/tex]plugging the values given we have:
[tex]\begin{gathered} F=\frac{(157)(18.5)^2}{5.8} \\ F=9264.35 \end{gathered}[/tex]Therefore, the normal force is 9264.35 N
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