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The following data represents the body temperature in degrees Fahrenheit of randomly selected adults:

98.4, 99.2, 98.9, 99.6, 99.5, 98.0, 99.4, 98.1, 98.8, 98.7

Use Excel to compute the values indicated below. Express your answers rounded to the nearest tenth.

- Mean:
- Standard Deviation:

Use the 68-95-99.7 Rule to answer the following question:

What is the probability of a body temperature less than 99.5?

Express your answer rounded to four decimal places.

Answer :

Mean is 98.8

Standard Deviation is 0.6

Probability is 0.8790

What is the value?

Mean:

=AVERAGE(A1:A10)

=98.8

Standard Deviation:

=STDEV.S(A1:A10)

=0.6

Using the 68-95-99.7 Rule, we can assume a normal distribution. The probability of a body temperature less than 99.5 is the area to the left of 99.5 under the normal curve.

z-score:

=(99.5 - 98.8) / 0.6

=1.17

Using the standard normal distribution table (z-table), we find:

Probability:

=P(Z

≈0.8790

So, the probability of a body temperature less than 99.5 is approximately 0.8790.

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