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Answer :
To find the potential energy of the bicycle at the top of a hill, you can use the formula for gravitational potential energy:
[tex]\[ PE = m \times g \times h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex] on Earth),
- [tex]\( h \)[/tex] is the height above the ground (in meters).
Let's apply the values given in the problem:
1. The mass [tex]\( m \)[/tex] of the bicycle is 25 kg.
2. The acceleration due to gravity [tex]\( g \)[/tex] is 9.8 m/s².
3. The height [tex]\( h \)[/tex] of the hill is 3 meters.
Plug these values into the formula:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
Now, calculate the potential energy:
[tex]\[ PE = 25 \times 9.8 \times 3 = 735 \][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is 735 joules.
The correct answer is [tex]\( \boxed{735 \, \text{J}} \)[/tex].
[tex]\[ PE = m \times g \times h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex] on Earth),
- [tex]\( h \)[/tex] is the height above the ground (in meters).
Let's apply the values given in the problem:
1. The mass [tex]\( m \)[/tex] of the bicycle is 25 kg.
2. The acceleration due to gravity [tex]\( g \)[/tex] is 9.8 m/s².
3. The height [tex]\( h \)[/tex] of the hill is 3 meters.
Plug these values into the formula:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
Now, calculate the potential energy:
[tex]\[ PE = 25 \times 9.8 \times 3 = 735 \][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is 735 joules.
The correct answer is [tex]\( \boxed{735 \, \text{J}} \)[/tex].
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