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Which arrangement of the following period 5 elements orders them from smallest to largest atomic radius?

A. In; Rb; Sb; Sr; Te
B. In; Sb; Te; Rb; Sr
C. Te; Sb; In; Sr; Rb
D. Rb; Sr; In; Sb; Te

Answer :

Final answer:

The smallest to largest atomic radius arrangement of the period 5 elements is Te; Sb; In; Sr; Rb.


Explanation:

The atomic radius generally increases as you move down a group and decreases as you move across a period on the periodic table. In the given options, the arrangement that orders the period 5 elements from smallest to largest atomic radius is B: Te; Sb; In; Sr; Rb.


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