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Answer :
Let's solve the equation step-by-step:
We start with the equation:
[tex]\[ 4 \cdot 9^x = 20 \][/tex]
1. Isolate the exponential term:
To do this, divide both sides of the equation by 4:
[tex]\[ 9^x = \frac{20}{4} \][/tex]
Simplifying the right side, we get:
[tex]\[ 9^x = 5 \][/tex]
2. Solve for [tex]\(x\)[/tex] using logarithms:
To solve for [tex]\(x\)[/tex], we'll take the logarithm of both sides. You can use any logarithm base, but a common choice is the natural logarithm ([tex]\(\ln\)[/tex]) or common logarithm ([tex]\(\log_{10}\)[/tex]):
[tex]\[ x = \frac{\log(5)}{\log(9)} \][/tex]
This expression gives the exact value of [tex]\(x\)[/tex]. When computed using a calculator, this results in approximately [tex]\( x = 0.73 \)[/tex].
Therefore, the correct value of [tex]\(x\)[/tex] is [tex]\(0.73\)[/tex].
We start with the equation:
[tex]\[ 4 \cdot 9^x = 20 \][/tex]
1. Isolate the exponential term:
To do this, divide both sides of the equation by 4:
[tex]\[ 9^x = \frac{20}{4} \][/tex]
Simplifying the right side, we get:
[tex]\[ 9^x = 5 \][/tex]
2. Solve for [tex]\(x\)[/tex] using logarithms:
To solve for [tex]\(x\)[/tex], we'll take the logarithm of both sides. You can use any logarithm base, but a common choice is the natural logarithm ([tex]\(\ln\)[/tex]) or common logarithm ([tex]\(\log_{10}\)[/tex]):
[tex]\[ x = \frac{\log(5)}{\log(9)} \][/tex]
This expression gives the exact value of [tex]\(x\)[/tex]. When computed using a calculator, this results in approximately [tex]\( x = 0.73 \)[/tex].
Therefore, the correct value of [tex]\(x\)[/tex] is [tex]\(0.73\)[/tex].
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