Answer :

We are given that the area of the rectangle is
[tex]$$\text{Area} = 120 \text{ ft}^2$$[/tex]
and the width is
[tex]$$\text{Width} = 5 \text{ ft}.$$[/tex]

First, we find the length of the rectangle using the formula for the area:
[tex]$$\text{Area} = \text{Length} \times \text{Width}.$$[/tex]
Solving for the length gives
[tex]$$\text{Length} = \frac{\text{Area}}{\text{Width}} = \frac{120}{5} = 24 \text{ ft}.$$[/tex]

Next, the perimeter of a rectangle is calculated with the formula:
[tex]$$\text{Perimeter} = 2 \times (\text{Length} + \text{Width}).$$[/tex]
Substitute the known values:
[tex]$$\text{Perimeter} = 2 \times (24 + 5) = 2 \times 29 = 58 \text{ ft}.$$[/tex]

Thus, the perimeter of the sidewalk is
[tex]$$\boxed{58 \text{ feet}}.$$[/tex]

Thanks for taking the time to read A sidewalk was being poured It had an area of 120 square feet and a width of 5 feet What was its perimeter. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada