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A wrestling mat used for high school competition is shown. The wrestling circle has a diameter of 28 feet. The inner circle has a diameter of 10 feet. What is the approximate area of the large wrestling circle (not including the inner circle)? Round your answer to the

nearest tenths place.

A wrestling mat used for high school competition is shown The wrestling circle has a diameter of 28 feet The inner circle has a diameter

Answer :

Answer:

537.2 ft^2

Step-by-step explanation:

For this problem, we need to find the area of both the inner and outer circle and subtract the area of the outer circle from the area of the inner circle.

The equation for the area of a circle is:

A = πr^2

So we are given the diameters of the circles. We know that the diameter of a circle is twice the radius.

Let's find the area of the 10ft diameter circle:

A_Little = π(10/2)^2 = π(5)^2 = 25π

Let's find the area of the 28ft diameter circle:

A_Big = π(28/2)^2 = π(14)^2 = 196π

So the area of the big circle excluding the inner circle would be as follows:

196π - 25π = 171π

So 171π in terms of decimals rounded to the nearest tenth would be 537.2.

Cheers.

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Rewritten by : Barada

Area of big remain circle is 536.94 feet²

Area of circle:

Given that;

Diameter of big circle = 28 feet

Diameter of small circle = 10 feet

Find:

Area of big remain circle

Computation:

Radius of big circle = 28 / 2 = 14 feet

Radius of small circle = 10 / 2 = 5 feet

Area of big remain circle = π(R1² - R2²)

Area of big remain circle = 3.14(14² - 5²)

Area of big remain circle = 3.14(171)

Area of big remain circle = 536.94 feet²

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