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Two cars leave towns 510 kilometers apart at the same time and travel toward each other. One car's rate is 14 kilometers per hour less than the other's. If they meet in 3 hours, what is the rate of the slower car?

Answer :

Final answer:

To find the rate of the slower car, we can use the formula Speed = Distance/Time and set up an equation. By solving the equation, we find that the rate of the slower car is 78 km/hr.

Explanation:

To find the rate of the slower car, we need to first find the rate of the faster car. Let's assume the rate of the faster car is x km/hr. Then, the rate of the slower car would be (x-14) km/hr.

When they meet, the total distance covered by both the cars is 510 km. Since they meet in 3 hours, the combined speed of both cars is 510/3 = 170 km/hr

Using the formula: Speed = Distance/Time, we can write the equation (x) + (x-14) = 170. Solving this equation, we get x = 92 km/hr. Therefore, the rate of the slower car (x-14) would be 92 - 14 = 78 km/hr.

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